Question

A car accelerates uniformly from 18 km/hr to 36km/hr in 5 seconds. calculate A... acceleration..B....the distance covered by the car in that time..

Answer 1

Acceleration = Change in Velocity/Time
Change in Velocity = 36-18 = 18 km/h=5 m/s
Time= 5 Seconds
Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (5*5)+(1/2*1*5*5)
s=25+12.5 i.e., s=37.5 m
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Answer 2

Acceleration= Change in velocity / time
change in velocity= 36 - 18 = 18 km/h
t= 5.

a = 18/5 = 1 ms. { divided by 5/18 to convert ms

B.
Distance= speed × time
= 18× 5
= 90m