Question

a car accelerates uniformly from 18 km per hour to 36 km per hour in 5 second calculate the acceleration and the distance covered by the car in that time

Answer 1m/s square, 37.5m

Answer 1

hey dear
here is your answer

given data :

initial velocity (u) = 18 km/hr or 5 m/s

final velocity (v) = 36 km/hr or 10 m/s

time (t) = 5 seconds

to find : acceleration & distance travelled

here we go

solution : for acceleration

by using first equation of motion

v = u+at

10 = 5+5a

5a = 5

a = 1 m/s²

so, acceleration is 1 m/s²

solution : for distance

by using 3rd equation of motion

v² = u²+2as

(10)² = (5)²+2*1*s

100 = 25+2s

2s = 75

s = 37.5 meter

so, distance travelled is 37.5 meter

hope it helps :)

Answer 2

        v-u       10 -  5                          =   5/ 5 = 1 ms-2
 a=  ----  = --------
          t             5/3600 ( hours)

Speed in km/h ×5/18 = speed in m/s

Therefore acceleration is 1 ms-2

v^2 =u^2 + 2as
100 - 25 = 2as
s = 75 / 2×1 = 37.5 m

Here s stands for distance covered

V is final velocity

U is initial velocity

Thank u★★★
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