a car accelerates uniformly from 18 km per hour to 36 km per hour in 5 seconds calculate the distance at the distance and the acceleration cover by the car in that time
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a=(v-u)/t
a=(36-18)/3600×5
18/18000
=10 ki power -3 kmper second square
a=(36-18)/3600×5
18/18000
=10 ki power -3 kmper second square
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