one end of a ladder of 26 m length touches the top of a building and its other is at a distance of 10 m from the base of the building find the height of the building
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12
By Pythagoras theorem,
26²=10²+hieght²
676-100=height²
576=hieght²
√576=hieght²
24= hieght
26²=10²+hieght²
676-100=height²
576=hieght²
√576=hieght²
24= hieght
Answered by
0
adj* =26*-10*
adj*=576
so ,adj=√576
adj=24
adj*=576
so ,adj=√576
adj=24
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