Question

A car accelerates uniformly from 18Km/h to 13Km/h in 5s . calculate the acceleration and distance covered by the car in that time​

Answer 1

ANSWER:-

Acceleration= -0.278 and Distance=28.4m

EXPLANATION:-

Given, A car accelerates,

Initial velocity,u=18kmph

u=18×5/18 m/s

u=5m/s

Final velocity,v=13kmph

v=13×5/18 m/s

v=65/18 m/s

v=3.611...m/s Acceleration,a=? a=(v-u)/t

a=(3.61-5) /5s

a= -1.39/5

a= -0.278 m/s^2

Distance covered,s=? S=ut+1/2at^2

S=5×5+1/2×-0.278×(5)^2

S=25m+0.136×25s^2

S=25m+3.4m

S=28.4m

HOPE IT HELPS!!..