Question

a car accelerates uniformly from 18km/h to 36km/h in 5 sec calculate a)acceleration b) distance covered by the car in that time .

Answer 1

18×5/18=5 m/s
36×5/18=10 m/s
a) by v=u+at
10=5+a×5
10=5+5a
10-5=5a
a=5/5=1 m/d
B) by s=ut+1/2at^2
S= 5×5+1/2×1×5^2
S=25+1/2×25
75/2=37.5 m
Acceleration =1 m/s
Distance=37.5 m

Hope it helps u...