Question

in vector diagram shown in figure where (R) is the resultant of vector (A) and (B) if R=B÷1.41 then value of angle is

Answer 1

Answer:

(2). The value of the angle is 45°.

Explanation:

Given that,

$R = \dfrac{B}{\sqrt{2}}$

The resultant vector is

$R = \dfrac{B}{\sqrt{2}}$

$\dfrac{R}{B}=\dfrac{1}{\sqrt{2}}$

According to figure,

Base = A

Perpendicular = R

Hypotenuses = B

$Sin\theta = \dfrac{perpendicular}{Hypotenuses}$

$sin\theta=\dfrac{R}{B}$

$sin\theta=\dfrac{1}{\sqrt{2}}$

$\theta=sin^{-1}\dfrac{1}{\sqrt{2}}$

$\theta= 45^{\circ}$

Hence, The value of the angle is 45°.

Answer 2

Answer:

45°

Explanation:

2). The value of the angle is 45°.

Explanation:

Given that,

R = \dfrac{B}{\sqrt{2}}R=

2

B

The resultant vector is

R = \dfrac{B}{\sqrt{2}}R=

2

B

\dfrac{R}{B}=\dfrac{1}{\sqrt{2}}

B

R

=

2

1

According to figure,

Base = A

Perpendicular = R

Hypotenuses = B

Sin\theta = \dfrac{perpendicular}{Hypotenuses}Sinθ=

Hypotenuses

perpendicular

sin\theta=\dfrac{R}{B}sinθ=

B

R

sin\theta=\dfrac{1}{\sqrt{2}}sinθ=

2

1

\theta=sin^{-1}\dfrac{1}{\sqrt{2}}θ=sin

−1

2

1

\theta= 45^{\circ}θ=45

∘

Hence, The value of the angle is 45°.