A car accelerates uniformly from 18km to 36km in 5 s.calculate 1.the acceleration and 2.the distance covered by the car in that time.
kavyarock:
plzzz can someone answer this
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18km/h = 5m/s =u
36km/h = 10m/s =v
t=5s
a=(v-u) /t
=(10-5)/5
a=1m/s^2
v^2-u^2=2as
10^2-5^2=2*1*s
(100-25)/2=s
s=75/2=37.5
36km/h = 10m/s =v
t=5s
a=(v-u) /t
=(10-5)/5
a=1m/s^2
v^2-u^2=2as
10^2-5^2=2*1*s
(100-25)/2=s
s=75/2=37.5
thanks
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