Question

a car accelerates uniformly from 20km/h to 35km/h in 5 seconds. calculate the distance covered by the car in that time

Answer 1

Given, u = 20 km/h = 5.5 m/s
v = 35 km/h = 9.7 m/s
t = 5 sec
Distance = ?
Let distance be s.

Therefore, a = (v- u)÷t
a = (9.7 - 5.5)÷5 = 0.84 m/s²

Now,

S = ut + 1/2 at²
S = 5.5 × 5 + 1/2 ×0.84 × 5 × 5
S = 27.5 + 10.5
S = 38m

IF IT IS CORRECT , PLZ MARK AS BRAINLIEST!!

Answer 2

• What is Acceleration...???

• Change in the velocity of an object per unit time.

• Acceleration a = v-u/t

• S.I Unit : m/s²

• Here, u = initial velocity and v = final velocity.

         a = acceleration and t = time.

i) u = 20 km/h = 5.5 m/s

 v = 35 km/h = 9.7.. m/s

 t  =  5 second

 a = v-u/t

 a = 9.7 - 5.5 / 5

 a = 4.2 / 5

 a = 0.84 m/s²

ii) The Distance covered :

   s = ut + 1/2 at²

   Here, s = distance travelled by the object.

         t = time

         a = uniform acceleration.

         s = 5.5 × 5 + 1/2 ( 0.84 ) ( 5 )²

         s = 27.5 + 1/2 × 0.84 × 25

         s = 27.5 + 10.5

         s =  38m.