a car accelerates uniformly from 36 km per hour to 72 km per hour in 10 seconds calculate the acceleration and distance covered by car in that time
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Answered by
8
➡In C.G.S
36km/h = 36×5/18 = 10m/s
72km/h = 72×5/18 = 20m/s
➡Now,
Acceleration = (v-u)t
= (20-10)10
= 10/10
= 1m/s²
➡Distance = ut + 1/2 ×at²
= 10×10 + 1/2 × 1× (10)²
= 100+1/2×100
= 100+50
= 150 m
➡Hope it helps u
36km/h = 36×5/18 = 10m/s
72km/h = 72×5/18 = 20m/s
➡Now,
Acceleration = (v-u)t
= (20-10)10
= 10/10
= 1m/s²
➡Distance = ut + 1/2 ×at²
= 10×10 + 1/2 × 1× (10)²
= 100+1/2×100
= 100+50
= 150 m
➡Hope it helps u
Anonymous:
wrong
U have taken the V and U in km/h and acceleration is in m/s^2
am i ryt
yes
hmm
I forgot that in hurry
thnx
Now i have correct it
Yes..
Answered by
6
hope it will help u .....!!!
Attachments:
Hey change ur unit
150 m is correct
thnx
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