Question

A car accelerates uniformly from 36km/h to 72km/h in 15 seconds. Find the distance travelled by car in that duration

Answer 1

Hii..
Here is your answer..

Solution:-
Initial velocity=36km/h
$= > 36 \times \frac{5}{18}$
=>10m/s
Final velocity=72km/h
$= > 72 \times \frac{5}{18}$
=>20m/s
Time =15m
So
$= > acceleration = \frac{v - u}{t}$
$= > \frac{20 - 10}{15} \\ = > \frac{10}{15} \\ = > \frac{2}{3}$
Now,
Distance travelled=?
$= > s = ut + \frac{1}{2} a {t}^{2} \\ = > s = 10 \times 15 + \frac{1}{2} \times \frac{2}{3} \times {(15)}^{2}$
$= > s = 10 \times 15 + 75$
$= > s = 225m$
Hence,
Distance travelled=225m

Hope it helps uh...✌️✌️✌️