Question

.A car accelerates uniformly from 5m/s to 10 m/s in 5 s. Calculate its acceleration​

Answer 1

Initial velocity of the car (u)= 5 m/s

Final velocity of the car (v) = 10 m/s

Time taken for change in velocity (t)= 5 d

Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s²

Distance covered during these 5 seconds, is found using the relation

s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m

So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s

Answer 2

Answer:

Acceleration= 1 m/s²

Explanation:

u= 5m/s

v= 10m/s

t= 5s

$a = \frac{v - u}{t}$

$a = \frac{10 - 5}{5}$

$a = \frac{5}{5} = 1m {s}^{ - 2}$

Note-

• a= acceleration
• v= final velocity
• u= initial velocity
• t= time taken

Hope It Helps