Question

using rolls law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions chcl3 and Ch 2 CL 2 second NaCl as and H2O​

Answer 1

Answer:According to Raoult's law for any solution the partial vapour pressure of each volatile component in the solution in the solution is directly proportional to its mole fraciton.

p1=p∘1x1

(a) CHCl3andCH2Cl2 (l) both components are volatile liquids, the total pressure will be p=p1=x1p∘1+x2p∘2

=x1p∘1+(1−x1)p∘2=(p∘1−p∘2)x1+p∘2

where, p= total vapour pressure

p1= partial vapour pressure of component 1

p2 = partial vapous pressure of component 2

(b) NaCl (s) and H2O(l) both are non-valatile components.

Hence, for a solution containing non-volatile solute, the Raoult's law is applicable only to vaporisable compnent and total vapour pressure can be written as

p=p1=x1p∘1

Explanation:hope you will understand

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