Question

A car accelerates uniformly from 80 km per hr to 72 km per hr in 5 s

Answer 1

Acceleration = Change in velocity / Time
= v - u / t
72km/h = 72 × 5 / 18 m/s = 20m/s
54km/h = 54 × 5 / 18m/s = 15m/s
Acceleration = 20-15 / 10
= 5 /10
= 0.5 m/s²
To find distance we use the formula
v² = u² + 2aS here v is the final velocitiy (72km/h)
u is the initial velocity(54km/h)
a is the acceleration
S is the distance
20² = 15² + 2 × 0.5 × S
400 = 225 + 1×S
400 - 225 = S
S = 175 m
Therefore distance = 175m
hope it helps.
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Answer 2

initial velocity=80000m/s
final velocity=72000m/s
time =5 second
acceleration=(v-u)/time
=-8000/5
=-1600m/s
hope it helps you,
you do not written what had to find
when you written I added the answer