Question

A car accelerates uniformly from a velocity of 54 km/h to 36 km/h in 15 min. What is its acceleration ?​

Answer 1

Answer:

1.2 km/h

Explanation:

a= v-u÷t

a=36-54÷15

a=1.2

Answer 2

Answer:

we know

$a = \frac{v - u}{t}$

here

u= 54 km/h

$54 \times \frac{5}{18} = 15m /s$

v=36 km/h

$36 \times \frac{5}{18} = 10m /s$

T= 15 min=15×60=300 seconds

substituting the Value

$a = \frac{10 - 15}{300} \\ a = \frac{ - 5}{300}$

a=−0.016 m/s²