Question

Two identical heaters 240 V – 1000 W are connected in parallel across a supply of 240 V line, then the combined power is (a) 500 W (b) 1000 W (c) 1500 W (d) 2000 W
i want only right answer then i mark you brainliest no wrong answers i can report

Answer 1

Answer:

Let resistance of each heater be

R

Ω

Given that the power of each heater is 1000W when connecred across 240V.

So

1000

=

240

2

R

⇒

R

=

240

2

1000

Ω

When two heaters are connected in serises total resistance

2

R

=

240

2

500

Ω

Then total power consumed

=

240

2

240

2

500

=

500

W

Explanation:

I hope it will help you.