Two identical heaters 240 V – 1000 W are connected in parallel across a supply of 240 V line, then the combined power is (a) 500 W (b) 1000 W (c) 1500 W (d) 2000 W
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Answer:
Let resistance of each heater be
R
Ω
Given that the power of each heater is 1000W when connecred across 240V.
So
1000
=
240
2
R
⇒
R
=
240
2
1000
Ω
When two heaters are connected in serises total resistance
2
R
=
240
2
500
Ω
Then total power consumed
=
240
2
240
2
500
=
500
W
Explanation:
I hope it will help you.
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