a car accelerates uniformly from an initial velocity of 2m/5 to finql velocity of 10/5 in 8sec it then slows down to a final velocity of 4m/5 in six seconds. calculate the acceleration of the car during the first 8sec and during the last 6sec
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hii
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here in first case
initial velocity of the car(u)=2/5 m/s
final velocity of the car (v)=10/5 m/s or 2 m/s
time (t)=8 sec
accleration= ?
using the equation a=v-u
t
a = 2-2/5
8
a=10/5-2/5
8
a = 8/40
a= 1/5 m/s
_____________________________________________________________
Now in second case
initial velocity of the car(u)=10/5 m/s or 2 m/s
final velocity of the car (v)=4/5 m/s
time (t)=6 sec
accleration= ?
using the equation a=v-u
t
a = 4/5-2
6
a=4-10
5
6
a= -6/5/6/1
a= -6/30
a= -1
5
____________________________________________________________
if helpful mark as brainliest
-----------------------------------------------------------------------------------------------------
here in first case
initial velocity of the car(u)=2/5 m/s
final velocity of the car (v)=10/5 m/s or 2 m/s
time (t)=8 sec
accleration= ?
using the equation a=v-u
t
a = 2-2/5
8
a=10/5-2/5
8
a = 8/40
a= 1/5 m/s
_____________________________________________________________
Now in second case
initial velocity of the car(u)=10/5 m/s or 2 m/s
final velocity of the car (v)=4/5 m/s
time (t)=6 sec
accleration= ?
using the equation a=v-u
t
a = 4/5-2
6
a=4-10
5
6
a= -6/5/6/1
a= -6/30
a= -1
5
____________________________________________________________
if helpful mark as brainliest
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