If x²-3x+2 is a factor of the polynomial x⁴-ax³+b, then find the values of a and b
Answers
Answered by
15
(x² -3x + 2) is a factor of x⁴ -ax³ + b ,
here ,
x² - 3x + 2
= x² -2x - x + 2
=(x -1)(x -2)
hence,
(x -1) and (x -2) are the factors of x⁴ - ax³ + b .
so, x = 1 and 2 are the zeros of x⁴ - ax³ + b
put x= 1 in x⁴ -ax³ + b
(1)⁴ -a(1)³ + b = 0
1 - a + b = 0
a - b = 1 -----(1)
now,
put x = 2 in x⁴ -ax³ + b
(2)⁴ - a(2)³ + b = 0
16 - 8a + b = 0
8a - b = 16 --------------(2)
solve equation (1) and (2)
8( b + 1) - b = 16
8b + 8 - b = 16
b = 8/7 and a = 15/7
here ,
x² - 3x + 2
= x² -2x - x + 2
=(x -1)(x -2)
hence,
(x -1) and (x -2) are the factors of x⁴ - ax³ + b .
so, x = 1 and 2 are the zeros of x⁴ - ax³ + b
put x= 1 in x⁴ -ax³ + b
(1)⁴ -a(1)³ + b = 0
1 - a + b = 0
a - b = 1 -----(1)
now,
put x = 2 in x⁴ -ax³ + b
(2)⁴ - a(2)³ + b = 0
16 - 8a + b = 0
8a - b = 16 --------------(2)
solve equation (1) and (2)
8( b + 1) - b = 16
8b + 8 - b = 16
b = 8/7 and a = 15/7
Similar questions