Question

a car accelerates with 4m/s after start,then find the displacement of car in 2 seconds​

Answer 1

GIVEN:

• Acceleration of the car = 4 m/s²
• Initial Velocity (u) = 0 (car starts from rest)
• Time taken by the car = 2 seconds

TO FIND:

• What is the displacement of the car ?

SOLUTION:

Firstly, we have to find the final velocity of the car

Let the final velocity of the car be 'v' m/s

To find the final velocity of the car, we use the first equation of motion:-

$\Large{\boxed{\bf{\star \: v = u + at \: \star}}}$

According to question:-

On putting the given values in the formula, we get

$\sf{\longmapsto v = 0 + 4 \times 2}$

$\sf{\longmapsto v = 0 + 8 }$

$\bf{\longmapsto v = 8 \: m/s }$

• Final velocity = v = 8 m/s

Let the displacement of the car be 'D' m

We know that the formula for finding the displacement of the car is:-

$\large{\boxed{\bf{\star \: VELOCITY = \dfrac{DISPLACEMENT}{TIME} \: \star}}}$

According to question:-

$\sf{\longmapsto 8 = \dfrac{D}{2}}$

$\sf{\longmapsto 8 \times 2 = D }$

$\bf{\longmapsto 16 \: m = D }$

• Displacement = D = 16 m

❝ Hence, the displacement of the car is 16 m ❞

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Answer 2

QUESTION:-

✯.ᴀ ᴄᴀʀ ᴀᴄᴄᴇʟᴇʀᴀᴛᴇs ᴡɪᴛʜ 4ᴍ/s ᴀғᴛᴇʀ sᴛᴀʀᴛ,ᴛʜᴇɴ ғɪɴᴅ ᴛʜᴇ ᴅɪsᴘʟᴀᴄᴇᴍᴇɴᴛ ᴏғ ᴄᴀʀ ɪɴ 2 sᴇᴄᴏɴᴅs

ANSWER✔

$\Large\underline\bold{GIVEN,}$

$\sf\dashrightarrow acceleration\:(a)= 4m/s^2$

$\sf\dashrightarrow initial\:velocity\:(u)= 0$

$\sf\dashrightarrow time\:taken=2 seconds$

$\Large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow displacement\:of\:car$

ACCORDING TO THE QUESTION,

$\sf\therefore taking \:two\:cases,$

$\sf\therefore in\:case\:1\: we\:will\:find\:the\:velocity\:of\:car$

$\sf\therefore in\:case\:2\:we\:will\:find\:the\: displacement\:of\:the\:car$

$\Large\underline\bold{SOLUTION,}$

$\large {\fbox { CASE:-1}}$

$\sf\therefore finding\:the\:final\:velocity\:of\:car$

FORMULA USED,

$\sf\large\therefore v=u+at$

$\sf\therefore acceleration\:(a)= 4m/s^2$

$\sf\therefore initial\:velocity\:(u)= 0$

$\sf\therefore time\:taken=2 seconds$

$\sf{\implies v = 0 + 4 \times 2}$

$\sf{\implies v = 0 + 8 }$

$\sf{\implies v = 8 m/s }$

$\sf\therefore final\:velocity\:=8m/s$

$\sf{\boxed{\sf{final\:velocity\:of\:the\:car\:is\:8m/s}}}$

$\large {\fbox {CASE:-2 }}$

$\sf\therefore finding\:the\: displacement\:of\:the\:car$

FORMULA USED,

$\sf\large\therefore VELOCITY = \dfrac{DISPLACEMENT}{TIME}$

$\sf{\implies 8 = \dfrac{D}{2}}$

$\sf{\implies 8 \times 2 = D }$

$\bf{\implies 16 m = D }$

$\sf{\boxed{\sf{d=16m}}}$

$\large{\boxed{\sf{displacement\:of\:the\:car=16m}}}$

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