A car acceleration from 36 km/h to 72 km/h on covering a distance of 50 m. calculate the acceleration of the car and the time taken to cover a distace of 50 m
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u=36
v=72
s=50m
using v square = u square + 2as
(72) square = 36 square+ 2a50
5184=1296+ 2a50
5184-1296=100a
3888=100a
a=3.888
now time v=u+at
72=36+3.888*t
36-3.888=t
32
t= 32
v=72
s=50m
using v square = u square + 2as
(72) square = 36 square+ 2a50
5184=1296+ 2a50
5184-1296=100a
3888=100a
a=3.888
now time v=u+at
72=36+3.888*t
36-3.888=t
32
t= 32
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