A car acceleration from 36 km/h to 72 km/h on covering a distance of 50 m. calculate the acceleration of the car and the time taken to cover a distace of 50 m?
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final velocity, v=72 kmph
initial velocity,u=36 kmph
distance covered,s=50
(v^2-u^2)/2*s = a
a= (v-u)/t
t= (v-u)/a
initial velocity,u=36 kmph
distance covered,s=50
(v^2-u^2)/2*s = a
a= (v-u)/t
t= (v-u)/a
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