A car acceleration from rest at 2.0 m/s^2 for 5 s
Answers
Answered by
1
, velocity = acceleration × time
=. 2.0 ×5
= 10 ms-1
hope it helps !
thank you !
=. 2.0 ×5
= 10 ms-1
hope it helps !
thank you !
Answered by
0
Hey dear here is your answer!!!!!!!
________________
According to question ;
u (initial velocity ) = 0 m/s
v (final velocity)=?
a (acceleration) = 2m/s^2
t (time) = 5sec
______
⏭️From first eq. of motion we can find v
⏭️v= u+ at
⏭️v= 0+2(5)
⏭️v= 10m/s
______
⏭️ You can also find distance by using second equation of motion ,
⏭️s= ut+1/2at^2
⏭️S= 1/2*2*25
⏭️S = 25m
________________
⏭️⭐ Hope it helps u dear....⭐⏭️
________________
According to question ;
u (initial velocity ) = 0 m/s
v (final velocity)=?
a (acceleration) = 2m/s^2
t (time) = 5sec
______
⏭️From first eq. of motion we can find v
⏭️v= u+ at
⏭️v= 0+2(5)
⏭️v= 10m/s
______
⏭️ You can also find distance by using second equation of motion ,
⏭️s= ut+1/2at^2
⏭️S= 1/2*2*25
⏭️S = 25m
________________
⏭️⭐ Hope it helps u dear....⭐⏭️
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