Question

a car accerlates from 36 kilometre per hours to 72 kilometre per hour in 10 seconds calculate accerlation and distance covered in 10 seconds​

Answer 1

Given :

• initial velocity = 36 km / hr
• final velocity = 72 km / hr
• time taken = 10 seconds

Unit conversion :

In order to convert km / hr into m / s multiply by 5 / 18

$u = 36 \times \frac{5}{18} = 10 \frac{m}{s}$

$v = 72 \times \frac{5}{18} = 20 \frac{m}{s}$

Solution :

By using first kinematic equation ,

$\boxed{ \blue{v = u + at}}$

here ,

• v= final velocity
• u = initial velocity
• a = acceleration
• t = time taken

substituting the given values in the above equation we get,

$\implies{20 = 10 + a \times 10}$

$\implies{10 = 10a}$

$\boxed{ \red{a = 1 \frac{m}{ {s}^{2} } }}$

By using the second kinematic equation ,

$\boxed{ \blue{s = ut + \frac{1}{2} a {t}^{2} }}$

here ,

• s= distance

substituting the given values in the above equation we get,

$\implies{s = 10 \times 10 + \frac{1}{2} \times 1 \times 100}$

$\boxed{ \red{s = 150 \: m}}$