Question

find the remainder when X^3-ax^2+6x-a is divided by x-9​

Answer 1

Step-by-step explanation:

p(x)=x³-ax²+6x-a

x-9 is a factor so x=9

p(9)=0

(9)³-a(9)²+6(9)-a=9

729-81a+54-a=9

-82a+783=9

-82a= -774

a= -774/-82

a= 774/82

a= 9.3 (approx.)