Question

a car acclerates uniformly on a syraight road from rest to a speed of 180kmh-1 in 25 s .find the distance covered by the car in this time interval...

Answer 1

intial velocity = 0
final velocity = 50 ms^2, also time = 25 s
acceleration = v-u/t
50-0/25
50/25
2 ms ^-2
distance = ut + 1/2 at^2
(0×25) + (1/2 × 2 × 25 ×25)
0 + 625
625 m
hope it helps u..

Answer 2

u=0 v=180km h convert ms 180×5/18=50 ms t=25
a=v-u/t
a=50-0/25
a=50/25
a=2ms

s=ut+1/2at^2
s=0×25+1/2×2×25×25
s=0+625
s=625m