Question

A car achieves a speed of 40m/s by undergoing uniform acceleration of 5m/s². Find the initial speed of the car

Answer 1

Explanation:

here

final velocity(v)=40m/s

uniform acceleration(a)=5m/square

initial velocity(u)=?

aceleration= initial velocity+ final velocity/3

5m/s square= u+40mls/2

10 =u + 40

u=40-10

U=30m/s

so the initial velocity is 30m/s

Answer 2

Given:-

A car achieves a speed of 40m/s by undergoing uniform acceleration of 5m/s² in 3sec.

To Find:-

Initial speed (u) of the car.

Equation used:-

First Equation of Motion : v = u + at

Here,

u = Initial Velocity

v = Final Velocity

a = Acceleration

t = Time

Solution:-

Using, v = u + at

where,

v = 40 m/sp

a = 5 m/s²

t = 3 sec

Putting values,

$\sf :\implies\: 40 = u +5\times3:$ ⟹40=u+5×3

$\sf :\implies\: 40 = u +15:$ ⟹40=u+15

$\sf :\implies\: u = 40-15:$ ⟹u=40−15

$\bf :\implies\: u = 25 \:ms^{-1}:$ ⟹u=25ms

−1

Hence, The Initial Speed of the Car is 25 m/s.

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