Question

. A car acquires a speed of 36 km/h in 10 s after the start. calculate the acceleration of the car. *

1 point

1 meter per second square

1.5 meter per second square

2 meter per second square

None of these​

Answer 1

Given :

• Initial velocity of the car = 0 m/s

• Final velocity of the car = 36 km/h

• Time = 10 seconds

To find :

• Acceleration of the car

Solution :

To calculate the acceleration of the car we will use the first equation of motion :-

First equation of motion :-

$\boxed{ \bf{ \red{v = u + at}}}$

where,

• v denotes the final velocity

• u denotes the initial velocity

• a denotes the acceleration

• t denotes the time

we have,

• v = 36 km/h

• u = 0 m/s

• a = ?

• t = 10 s

Firstly, convert the final velocity of the car from km/h into m/s.

To convert it from km/h into m/s mulitply by 5/18

→ Final velocity = 36 × 5/18

→ Final velocity = 2 × 5

→ Final velocity = 10

Therefore, final velocity = 10 m/s

Now, substitute the values in the first equation of motion :-

→ 10 = 0 + a × 10

→ 10 = a × 10

→ 10 ÷ 10 = a

→ 1 = a

→ The value of a = 1

Therefore, the acceleration of the car = 1 m/s²

Know MorE :

The S.I. units of velocity, acceleration and time are m/s, m/s² and s respectively.

Second equation of motion :-

• s = ut + ½ at²

Third equation of motion :-

• v² - u² = 2as

where,

• s denotes the distance/displacement