Physics, asked by priyanshir955, 7 months ago

A car acquires a velocity 72 kmph in 108
Starting from sest. călculate its average
velocity , acceleration and distance travelled
during this period.​

Answers

Answered by harshkrishnan
4

Answer:

Hey there !

Initial Velocity = u = 0

Final velocity = v = 72 km/hr = 72 x 5/18 = 20 m/s

Time = t = 10 sec

Acceleration = a

Equation of motion :-

v = u + at

20 = 0 + 10a

a = 20/10

a = 2 m/s²

displacement = distance traveled = s

Equation of motion :-

v² - u² = 2as

20² = 2 × 2 × s

400 = 4s

s = 400/4

s = 100 m

Average velocity = displacement / time

= 100 / 10

= 10 m/s

Hope this helps you !

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