Question

A car acquires a velocity of 72 km/h in 10 seconds starting from rest. find
a.the accn
b.average velocity
c.distance travelled.

Answer 1

Given that:-
Initial velocity (u) = 0
Final velocity = 72km/h
= 20m/s
Time taken (t) = 10s

a) acceleration =(v-u)/t
=(20-0)/10
= 2m/s^2
b) average velocity = (v+u)/2
=(20+0)/2
=20/2
=10m/s
c) let distance be s
Using second equation of motion
=ut+(1/2)at^2
= (0)(10)+(1/2)(2)(10)^2
= 0+100
= 100
So, the distance covered by the body was 100m.

Answer 2

Answer: 100m

Explanation: Given that:-

Initial velocity (u) = 0

Final velocity = 72km/h

= 20m/s

Time taken (t) = 10s

a) acceleration =(v-u)/t

=(20-0)/10

= 2m/s^2

b) average velocity = (v+u)/2

=(20+0)/2

=20/2

=10m/s

c) let distance be s

Using second equation of motion

=ut+(1/2)at^2

= (0)(10)+(1/2)(2)(10)^2

= 0+100

= 100

So, the distance covered by the body was 100 m