Question

A car acquires a velocity of 72 km/h in 10s starting from rest. Find
(a) accleration (b) distance travelled (c) average velocity​

Answer 1

Answer:

Explanation:

Given that:-

Initial velocity (u) = 0

Final velocity = 72km/h

= 20m/s

Time taken (t) = 10s

a) acceleration =(v-u)/t

=(20-0)/10

= 2m/s^2

b) average velocity = (v+u)/2

=(20+0)/2

=20/2

=10m/s

c) let distance be s

Using second equation of motion

=ut+(1/2)at^2

= (0)(10)+(1/2)(2)(10)^2

= 0+100

= 100

So, the distance covered by the body was 100m.

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