A car acquires a velocity of 72 kmph in 10 s starting from rest. calculate its average velocity , acceleration and distance travelled during this period.
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Answered by
4
Explanation:
ANSWER
v=72 km/h=
3600
72×1000
=20 m/s
Acceleration a=
t
v−u
=
10s
(20−0) ms
−1
=2 ms
−2
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Answered by
0
Explanation:
v=72 km/h=
3600
72×1000
=20 m/s
Acceleration a=
t
v−u
=
10s
(20−0) ms
−1
=2 ms
−2
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