A car acquires a velocity of 72 kmph in 10s after starting from rest.THEN..
i)acceleration of the car.
ii)average velocity of the car.
iii)distance travelled by the car.
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Answered by
5
Let's first convert to SI-units:
The speed of 72km1h=72000m3600s=20m/s
(1) Then the acceleration :
a=Δvt=20m/s−0m/s10s=2m/s2
(2) The average speed :
¯v=72km/h−0km/h2=36km/hor20m/s−0m/s2=10m/s
(3) Distance travelled:
s=¯v⋅t=(10m/s)⋅(10s)=100m
The speed of 72km1h=72000m3600s=20m/s
(1) Then the acceleration :
a=Δvt=20m/s−0m/s10s=2m/s2
(2) The average speed :
¯v=72km/h−0km/h2=36km/hor20m/s−0m/s2=10m/s
(3) Distance travelled:
s=¯v⋅t=(10m/s)⋅(10s)=100m
Answered by
3
hope this would help u......please mark it as brainiest
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