Physics, asked by layla19, 2 months ago

A car approaches a highway on-ramp it increases its velocity from 11m/s[N] to 25m/s[N] over 12s. What is the car’s average acceleration?

Answers

Answered by dharamkush18

0

Answer:

Explanation:

v1=11 m/s

v2= 25 m/s

t=12 s

a=(v2-v1)/t

a=(25-11)/12=1.16m/s^2

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