Question

A car aqquires a velocity of 72 km/hrs in 10 seconds starting from rest.Find (a)the acceleration (b)the average velocity and (c)the distance travelled in this time

Answer 1

u = 0 ms
v = 72 kmh = $[72*1000]/3600$ = 20 ms
t = 10 s

 acc. = $[v-u]/t$ = (20-0)/10 = 20/10 = 2 ms^-2

avg velocity = $(u+v) / 2$ = (0+20)/2 = 20/2 = 10 ms

distance (s) = $ut + 1/2(at^2)$ = (0)(10) + (1/2)(2)(10)(10) = 100 m


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