Question

if polynomials ax^3+3x^2-13 and 2x^3-5x+a when divided by x-2 leaves the same remainder. Find the value of a

Answer 1

value of x = 2 ( simplifing x - 2 )
so ,
8a + 12 - 13 = 16 - 10 + a ( after putting x= 2 )
8a - a = 16 -10 -12 + 13
7a = 6 + 1
7a = 7
a = 1
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Answer 2

Answer:

Hey mate here is your answer.

A=1

Explanation:

x-2 is the factor .

X=2.

As in the question they mentioned that remainder is equal in both of the cases, we need to equate them.

8a+12-13=16-10+a

8a-2=16-10-12+13

7a=6+1

7a=7

a=7.

Therefore value of a is 7.

Thank you.

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