Question

A car aquires velocity of 72 km/sec ,10 sec after start . Find accerelaration and distance travelled​

Answer 1

Answer:

acceleration = 7.2 km/ sec^2

distance = 720 km

Explanation:

FORMULAS :-

acceleration = velocity / time

distance = velocity × time

Given :-

• velocity of 72 km/sec
• time = 10 sec

Solution :-

$accelertion \: = \frac{72}{10} \frac{km}{ {sec}^{2} } = 7.2 \frac{km}{ {sec}^{2} }$

$distance \: = 72 \frac{km}{sec} \times 10sec \: = 720 \: km$