a car aquries a velocity of 72 km/ h in 10 seconds starting from rest . find (a)the acceleration (b)the average velocity (c)the distance travelled in this time
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Hey.
Here is the answer.
u = 0
v = 72 km/h = 72×5/18 = 20 m/s
t = 10 s
a) as V = u + a t
so, 20 = 0 + a × 10
or, a = 20/10 = 2 m/s^2
so, acceleration is 2 m/s^2
b) average velocity= (v + u ) /2
= 20/2
= 10 m/s
c) the distance travelled in this time ,
s = u t + 1/2 a t^2
or, s = 0 + 1/2 ×2× 10^2
= 100 m
Thanks.
Here is the answer.
u = 0
v = 72 km/h = 72×5/18 = 20 m/s
t = 10 s
a) as V = u + a t
so, 20 = 0 + a × 10
or, a = 20/10 = 2 m/s^2
so, acceleration is 2 m/s^2
b) average velocity= (v + u ) /2
= 20/2
= 10 m/s
c) the distance travelled in this time ,
s = u t + 1/2 a t^2
or, s = 0 + 1/2 ×2× 10^2
= 100 m
Thanks.
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