A car at 1000 kg is moving with velocity of 18 km/hr. If a retarding (brake) force of 1000 N is appli
on it then distance travelled by it after applying brake will be -
(A) 1 m
(B) 162 m
(C) 12.5 m
(D) 144 m
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Answer:1m
Explanation:F=ma
1000N=1000(a)
a=1m/s
so distance travelled after applying break is 1m because it has more mass and force is more but acceleration is less
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