Question

A CAR AT A REST STARTS TO TRAVEL IN A STRAIGHT PATH.IT REACHES A VELOCITY OF 12 M/S IN 4s.WHAT IS ITS ACCELERATION .ASSUMING THAT IT ACCELERATES UNIFORMLY?

Answer 1

Answer:

Explanation:

Since the car has been at rest, the initial velocity ( u ) = 0 m/s

final velocity ( v ) = 12 m/s

time taken = 4s

therefore,

acceleration = v - u / t

                     = 12 - 0 / 4 = 12/4

                     = 3$m/s^{2}$

hence, the acceleration is 3m/s^2.

hope this helps!

Answer 2

Answer:

answer= 3m/s²

Explanation:

12 is final acceleration 0 is initial acceleration

acceleration = change in velocity

                     __________________

                           time

so 12/4 = 3

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