Question

A car at rest accelerate uniformly to a speed of 90 km h in 30 sec. How much distance is covered by the car?

Answer 1

Explanation:

We know,

A=change in velocity/time taken=v-u/t

Initial velocity(u)= 0

Final velocity(v)=90kmph=25m/s(From kmph to mps=90×5/18)

Time(t)= 30 sec

So, 25–0/30=5/6m/s.

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Answer 2

Explanation:

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