Question

A car at rest accelerates uniformly to a speed of 144
km h-1 in 20 s. How much distance is covered by the car ?
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Answer 1

Step-by-step explanation:

s=ut+1/2at^2

u=0

now,a=?

v=u+at

a=v/t

v=144*(5/18)=40m/s

a=40/20=2m/s^2

s=1/2*2*(20)^2=400m