Question

A car at rest has mass of 1000 Kg it is moved by a horizontal force of 50 N on a horizontal surface calculate the work done by the force in 8 sec​

Answer 1

Answer:

If a be the acceleration of the car, ma=F or a=F/m=50/1000=0.05m/s

2

Using S=ut+

2

1

at

2

, the displacement in 8 s is S=0(8)+0.5(0.05)(8)

2

=1.6m

Work done W=FS=50(1.6)=80J

Answer 2

Explanation:

If a be the acceleration of the car, ma=F or a=F/m=50/1000=0.05m/s²

Using S=ut+ ½ at ² , the displacement in 8 s is S=0(8)+0.5(0.05)(8)²=1.6m

Work done W=FS=50(1.6)=80J