A car attains a velocity of 36km/h after accelerating uniformly from the rest in 5s. Find the distance traveled.
Answers
Answered by
66
We can calculate this question using the kinematic equations (SUVAT equations):
⇒Since in this question we have the initial velocity, from rest(u = 0 km/hr) and final velocity (v = 36km/hr) and time of 5 seconds, we will use the following kinematic equation:
S = 1/2 ( u + v) t
where S is the distance( displacement), u is the initial velocity ( 0 km/hr), v is the final velocity(36km/hr) and t is time taken(5 secs).
convert 36km/hr to m/s ⇒ 36km/hr × 10/36 = 10m/s
S = 1/2 ( 0 + 10) 5
S = 1/2 × 10 × 5
S = 5 × 5
S = 25 meters
Therefore the distance traveled by this car is 25 meters.
⇒Since in this question we have the initial velocity, from rest(u = 0 km/hr) and final velocity (v = 36km/hr) and time of 5 seconds, we will use the following kinematic equation:
S = 1/2 ( u + v) t
where S is the distance( displacement), u is the initial velocity ( 0 km/hr), v is the final velocity(36km/hr) and t is time taken(5 secs).
convert 36km/hr to m/s ⇒ 36km/hr × 10/36 = 10m/s
S = 1/2 ( 0 + 10) 5
S = 1/2 × 10 × 5
S = 5 × 5
S = 25 meters
Therefore the distance traveled by this car is 25 meters.
Answered by
20
Explanation:
U is equal to zero because it starts from rest.
V= 36 KMPH
convert 36 kilometre per hour into metre per second .
therefore we equals to 10 m/ s.
S= u+ v /2 × t
= 0+10/2 × 5
=5×5
=25 m
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