Physics, asked by suyogbhandari2063, 1 month ago

A car attains a velocity of 72km\hr after 15 seconds from starting. Calculate the acceleration and the distance travelled in this time.

Answers

Answered by rishisubhodeep12
1

Answer:Initial Velocity = u = 0  

Final velocity = v=72km/hr=72×  

18

5

​  

=20m/s

Time = t = 10 sec

Acceleration = a

Equation of motion :-

v=u+at

20=0+10a

a=  

10

20

​  

 

a=2m/s  

2

 

displacement = distance traveled = s

Equation of motion :-

v =u+  

2

=2as

20  

2

=2×2×s

400=4s

s=  

4

400

Answered by ny7616704
0

A car attains a velocity of 72km\hr after 15 seconds from starting. Calculate the acceleration and the distance travelled in this time.

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