Question

a car begins at a speed of 3m/s and accelerates at 2m/s^2 over a distance of 40m calculate final speed of car​

Answer 1

Answer:

Initial Velocity (u) = 3 m/s

Acceleration (a) = 2 m/s²

Distance Covered (S) = 40 m

v² = u²+2aS

v² = 3²+2*2*40

v² = 9+160

= v² = 169

= v = 13 m/s

Hope this helps.

Answer 2

Answer:

Initial Velocity (u) = 3 m/s

Acceleration (a) = 2 m/s²

Distance Covered (S) = 40 m

v² = u²+2aS

v² = 3²+2*2*40

v² = 9+160

= v² = 169

= v = 13 m/s