Question

A car change its velocity from 60 km/h to 90 km/h in 10 seconds .
calculate
(i) Acceleration
(ii) distance travelled by the car

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Answer 1

Answer:

Here,

Initial velocity=60km=60000m

Final velocity=90km=90000m

Time=10 sec

1)acceleration=final velocity-initial velocity/ time

=90000-60000/10

=30000/10

=3000m/s^2

2) distance=initial velocity ×time +1/2acceleration ×time^2

(by using position time relation)

That is,

s=ut+1/2at^2

=60000×10+1/2×3000×(10)^2

=600000+15000×100

=600000+1500000=2100000m