Question

1.31
14. The pressure of the water vapour of a solution containing a nonvolatile solute is 2% below that of the
vapour
of pure water. Determine the molality of the solution.
(1.134 m)
po
Solvent
-Po
Solution
2​

Answer 1

Answer:

Let P° be the vapour pressure of water.

Ps = vapour of the solution.

Formulae :

( P° - Ps) / Ps = (W × M) / (m ×W)

w / (m × W) × 1000 × M / 1000

Molality = (W ×1000) / (m × W)

(P° - Ps) / Ps = Molality × M/1000

Ps = 0.98P°

Substituting in the formulae :

(P° - 0.98P°) / 0.98P° = molality × 1000 / 18

Molality = 0.02 P° / 0.98 P° × 1000 /18

Molality = 1.133

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