A car changes it's velocity from 36km/hr to 72km /hr in 30sec calculate the distance travelled by the car within this time
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Hello!!
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We have
u = 36 km/h
= 10 m/s
v = 72 km/h
= 72× 100 / 60 × 60
= 7200/ 360
= 20 m/s
t = 10 second
We know
A = V- U / t
= 20 - 10 / 10
= 1 m/s ^2
Hence the acceleration of the bus after increasing it's speed is 1 m/s^2
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Hope it helpful
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