A car changes its speed from 20 km h-1 to 50 km h-1 of mass 3600 kg in 5 s. determine the net external force applied on the car.
Answers
Answered by
25
u=20km/hr
v= 50km/hr
mass= 3600kg
t= 5s
Acceleration= (v-u) /t= (50-20)/5=30/5= 6m/s2
According to the formula,
F=mass *acceleration
= 3600*6
= 21600N !!! ANSWER!!!
Mark BRAINLIEST And if possible FOLLOW
v= 50km/hr
mass= 3600kg
t= 5s
Acceleration= (v-u) /t= (50-20)/5=30/5= 6m/s2
According to the formula,
F=mass *acceleration
= 3600*6
= 21600N !!! ANSWER!!!
Mark BRAINLIEST And if possible FOLLOW
Answered by
12
Answer:
6000N
Step-by-step explanation:
Given,
Initial velocity ( u ) = 20 Kmh-1
Final velocity ( v ) = 50 kmh-1
Mass ( m ) = 3600 Kg
Time ( t ) = 5 s
Formula :
F = ma
F = m ( v-u / t )
Apply it
F = 3600 ( 50 - 20 / 5 )
F = 3600 ( 30/5 )
F = 3600 ( 6 )
F = 21600 Kg Kmh-1
Units are not in S.I system ( ms-1 )
So,
Have to multiply this by 5/ 18
21600 * 5/18
1200 * 5
6000 Kgms-1 (or) 6000 N
This is the answer!!!!
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