Question

a car comes to rest in 10seconds from 10m/s in covering a distance of 75metres. find the retardation provided by the breaks​

_____ answer me guy's fast _____​

Answer 1

✨Initial speed of the car   u=10 m/s

Initial speed of the car   u=10 m/sFinal speed of the car   v=0 m/s

Initial speed of the car   u=10 m/sFinal speed of the car   v=0 m/sAcceleration (or  retardation) of the car   a=−2 m/s

Initial speed of the car   u=10 m/sFinal speed of the car   v=0 m/sAcceleration (or  retardation) of the car   a=−2 m/sUsing   v2−u2=2aS

Initial speed of the car   u=10 m/sFinal speed of the car   v=0 m/sAcceleration (or  retardation) of the car   a=−2 m/sUsing   v2−u2=2aS∴   0−102=2(−2)S

Initial speed of the car   u=10 m/sFinal speed of the car   v=0 m/sAcceleration (or  retardation) of the car   a=−2 m/sUsing   v2−u2=2aS∴   0−102=2(−2)S⟹ S=2×2100=25 m✨

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Answer 2

Answer:

you are going on the business trip right. on the way think about it why you are getting possessive for me and getting insecure when you see me with someone.

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